4sin(2x)+-3cos(2x)=4

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Solution for 4sin(2x)+-3cos(2x)=4 equation:


Simplifying
4sin(2x) + -3cos(2x) = 4

Remove parenthesis around (2x)
4ins * 2x + -3cos(2x) = 4

Reorder the terms for easier multiplication:
4 * 2ins * x + -3cos(2x) = 4

Multiply 4 * 2
8ins * x + -3cos(2x) = 4

Multiply ins * x
8insx + -3cos(2x) = 4

Remove parenthesis around (2x)
8insx + -3cos * 2x = 4

Reorder the terms for easier multiplication:
8insx + -3 * 2cos * x = 4

Multiply -3 * 2
8insx + -6cos * x = 4

Multiply cos * x
8insx + -6cosx = 4

Reorder the terms:
-6cosx + 8insx = 4

Solving
-6cosx + 8insx = 4

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-8insx' to each side of the equation.
-6cosx + 8insx + -8insx = 4 + -8insx

Combine like terms: 8insx + -8insx = 0
-6cosx + 0 = 4 + -8insx
-6cosx = 4 + -8insx

Divide each side by '-6osx'.
c = -0.6666666667o-1s-1x-1 + 1.333333333ino-1

Simplifying
c = -0.6666666667o-1s-1x-1 + 1.333333333ino-1

Reorder the terms:
c = 1.333333333ino-1 + -0.6666666667o-1s-1x-1

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