4t(t-5)-2t(3t+2)+108=3t(2t-5)-t(8t-3

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Solution for 4t(t-5)-2t(3t+2)+108=3t(2t-5)-t(8t-3 equation: 



4t(t-5)-2t(3t+2)+108=3t(2t-5)-t(8t-3

We move all terms to the left:

4t(t-5)-2t(3t+2)+108-(3t(2t-5)-t(8t-3)=0

We multiply parentheses

4t^2-6t^2-20t-4t-(3t(2t-5)-t(8t-3)+108=0

We add all the numbers together, and all the variables

-2t^2-24t-(3t(2t-5)-t(8t-3)+108=0

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