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4t*5t=6t
We move all terms to the left:
4t*5t-(6t)=0
We add all the numbers together, and all the variables
-6t+4t*5t=0
Wy multiply elements
20t^2-6t=0
a = 20; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·20·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*20}=\frac{0}{40} =0 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*20}=\frac{12}{40} =3/10 $
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