4t+-2+t2=6+t2

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Solution for 4t+-2+t2=6+t2 equation: 



4t+-2+t2=6+t2

We move all terms to the left:

4t+-2+t2-(6+t2)=0

We add all the numbers together, and all the variables

-(+t^2+6)+4t+t2-2+=0

We add all the numbers together, and all the variables

t^2-(+t^2+6)+4t=0

We get rid of parentheses

t^2-t^2+4t-6=0

We add all the numbers together, and all the variables

4t-6=0

We move all terms containing t to the left, all other terms to the right

4t=6

t=6/4

t=1+1/2

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