4t+1=4(t-3)

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Solution for 4t+1=4(t-3) equation: 



4t+1=4(t-3)

We move all terms to the left:

4t+1-(4(t-3))=0



We calculate terms in parentheses: -(4(t-3)), so:

4(t-3)

We multiply parentheses

4t-12

Back to the equation:

-(4t-12)



We get rid of parentheses

4t-4t+12+1=0

We add all the numbers together, and all the variables

13!=0

There is no solution for this equation

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