4t+8/4t-3=2t+3/2t-5

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Solution for 4t+8/4t-3=2t+3/2t-5 equation:



4t+8/4t-3=2t+3/2t-5
We move all terms to the left:
4t+8/4t-3-(2t+3/2t-5)=0
Domain of the equation: 4t!=0
t!=0/4
t!=0
t∈R
Domain of the equation: 2t-5)!=0
t∈R
We get rid of parentheses
4t+8/4t-2t-3/2t+5-3=0
We calculate fractions
4t-2t+16t/8t^2+(-12t)/8t^2+5-3=0
We add all the numbers together, and all the variables
2t+16t/8t^2+(-12t)/8t^2+2=0
We multiply all the terms by the denominator
2t*8t^2+16t+(-12t)+2*8t^2=0
We add all the numbers together, and all the variables
16t+2t*8t^2+(-12t)+2*8t^2=0
Wy multiply elements
16t^3+16t^2+16t+(-12t)=0
We get rid of parentheses
16t^3+16t^2+16t-12t=0
We do not support etpression: t^3

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