4t-(6t+3)=(5t-2)+10t+2

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Solution for 4t-(6t+3)=(5t-2)+10t+2 equation:



4t-(6t+3)=(5t-2)+10t+2
We move all terms to the left:
4t-(6t+3)-((5t-2)+10t+2)=0
We get rid of parentheses
4t-6t-((5t-2)+10t+2)-3=0
We calculate terms in parentheses: -((5t-2)+10t+2), so:
(5t-2)+10t+2
We add all the numbers together, and all the variables
10t+(5t-2)+2
We get rid of parentheses
10t+5t-2+2
We add all the numbers together, and all the variables
15t
Back to the equation:
-(15t)
We add all the numbers together, and all the variables
-17t-3=0
We move all terms containing t to the left, all other terms to the right
-17t=3
t=3/-17
t=-3/17

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