4t-10=12+2(t+8)=10

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Solution for 4t-10=12+2(t+8)=10 equation:



4t-10=12+2(t+8)=10
We move all terms to the left:
4t-10-(12+2(t+8))=0
We calculate terms in parentheses: -(12+2(t+8)), so:
12+2(t+8)
determiningTheFunctionDomain 2(t+8)+12
We multiply parentheses
2t+16+12
We add all the numbers together, and all the variables
2t+28
Back to the equation:
-(2t+28)
We get rid of parentheses
4t-2t-28-10=0
We add all the numbers together, and all the variables
2t-38=0
We move all terms containing t to the left, all other terms to the right
2t=38
t=38/2
t=19

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