4t-10=12-2(t+8)

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Solution for 4t-10=12-2(t+8) equation: 



4t-10=12-2(t+8)

We move all terms to the left:

4t-10-(12-2(t+8))=0



We calculate terms in parentheses: -(12-2(t+8)), so:

12-2(t+8)

determiningTheFunctionDomain
-2(t+8)+12

We multiply parentheses

-2t-16+12

We add all the numbers together, and all the variables

-2t-4

Back to the equation:

-(-2t-4)



We get rid of parentheses

4t+2t+4-10=0

We add all the numbers together, and all the variables

6t-6=0

We move all terms containing t to the left, all other terms to the right

6t=6

t=6/6

t=1

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