4t-2(5)=-3(2t-1)

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Solution for 4t-2(5)=-3(2t-1) equation: 



4t-2(5)=-3(2t-1)

We move all terms to the left:

4t-2(5)-(-3(2t-1))=0



We calculate terms in parentheses: -(-3(2t-1)), so:

-3(2t-1)

We multiply parentheses

-6t+3

Back to the equation:

-(-6t+3)



We get rid of parentheses

4t+6t-3-25=0

We add all the numbers together, and all the variables

10t-28=0

We move all terms containing t to the left, all other terms to the right

10t=28

t=28/10

t=2+4/5

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