4t-2(t+5)=8+t+3

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Solution for 4t-2(t+5)=8+t+3 equation: 



4t-2(t+5)=8+t+3

We move all terms to the left:

4t-2(t+5)-(8+t+3)=0

We add all the numbers together, and all the variables

4t-2(t+5)-(t+11)=0

We multiply parentheses

4t-2t-(t+11)-10=0

We get rid of parentheses

4t-2t-t-11-10=0

We add all the numbers together, and all the variables

t-21=0

We move all terms containing t to the left, all other terms to the right

t=21

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