4t-2(t-9)=3(1+t)

Solution for 4t-2(t-9)=3(1+t) equation:

4t-2(t-9)=3(1+t)

We move all terms to the left:

4t-2(t-9)-(3(1+t))=0

We add all the numbers together, and all the variables

4t-2(t-9)-(3(t+1))=0

We multiply parentheses

4t-2t-(3(t+1))+18=0


We calculate terms in parentheses: -(3(t+1)), so:

3(t+1)

We multiply parentheses

3t+3

Back to the equation:

-(3t+3)


We add all the numbers together, and all the variables

2t-(3t+3)+18=0

We get rid of parentheses

2t-3t-3+18=0

We add all the numbers together, and all the variables

-1t+15=0

We move all terms containing t to the left, all other terms to the right

-t=-15

t=-15/-1

t=+15