4t-2-(t*t)=6+(t*t)

Solution for 4t-2-(t*t)=6+(t*t) equation:

4t-2-(t*t)=6+(t*t)

We move all terms to the left:

4t-2-(t*t)-(6+(t*t))=0

We add all the numbers together, and all the variables

4t-(+t*t)-(6+(+t*t))-2=0

We get rid of parentheses

4t-t*t-(6+(+t*t))-2=0


We calculate terms in parentheses: -(6+(+t*t)), so:

6+(+t*t)

determiningTheFunctionDomain
(+t*t)+6

We get rid of parentheses

t*t+6

Wy multiply elements

t^2+6

Back to the equation:

-(t^2+6)


Wy multiply elements

-1t^2+4t-(t^2+6)-2=0

We get rid of parentheses

-1t^2-t^2+4t-6-2=0

We add all the numbers together, and all the variables

-2t^2+4t-8=0

a = -2; b = 4; c = -8;
Δ = b2-4ac
Δ = 42-4·(-2)·(-8)
Δ = -48
Delta is less than zero, so there is no solution for the equation