4t-4(t-1)=3(t-2)

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Solution for 4t-4(t-1)=3(t-2) equation: 



4t-4(t-1)=3(t-2)

We move all terms to the left:

4t-4(t-1)-(3(t-2))=0

We multiply parentheses

4t-4t-(3(t-2))+4=0



We calculate terms in parentheses: -(3(t-2)), so:

3(t-2)

We multiply parentheses

3t-6

Back to the equation:

-(3t-6)



We add all the numbers together, and all the variables

-(3t-6)+4=0

We get rid of parentheses

-3t+6+4=0

We add all the numbers together, and all the variables

-3t+10=0

We move all terms containing t to the left, all other terms to the right

-3t=-10

t=-10/-3

t=3+1/3

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