4t2+32t+64=0

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Solution for 4t2+32t+64=0 equation: 



4t^2+32t+64=0

a = 4; b = 32; c = +64;
Δ = b2-4ac
Δ = 322-4·4·64
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{-32}{8}=-4$

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