4t2/3+28t1/3+49=0

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Solution for 4t2/3+28t1/3+49=0 equation: 


t in (-oo:+oo)

(4*t^2)/3+(28*t^1)/3+49 = 0

(4*t^2)/3+(28*t)/3+49 = 0

4/3*t^2+28/3*t+49 = 0

DELTA = (28/3)^2-(4/3*4*49)

DELTA = -1568/9

DELTA < 0

t belongs to the empty set

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