4u+2-2(-5u-2)=4(u-3)

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Solution for 4u+2-2(-5u-2)=4(u-3) equation:



4u+2-2(-5u-2)=4(u-3)
We move all terms to the left:
4u+2-2(-5u-2)-(4(u-3))=0
We multiply parentheses
4u+10u-(4(u-3))+4+2=0
We calculate terms in parentheses: -(4(u-3)), so:
4(u-3)
We multiply parentheses
4u-12
Back to the equation:
-(4u-12)
We add all the numbers together, and all the variables
14u-(4u-12)+6=0
We get rid of parentheses
14u-4u+12+6=0
We add all the numbers together, and all the variables
10u+18=0
We move all terms containing u to the left, all other terms to the right
10u=-18
u=-18/10
u=-1+4/5

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