4u+2-5(-2u-1)=2(u-1)

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Solution for 4u+2-5(-2u-1)=2(u-1) equation: 



4u+2-5(-2u-1)=2(u-1)

We move all terms to the left:

4u+2-5(-2u-1)-(2(u-1))=0

We multiply parentheses

4u+10u-(2(u-1))+5+2=0



We calculate terms in parentheses: -(2(u-1)), so:

2(u-1)

We multiply parentheses

2u-2

Back to the equation:

-(2u-2)



We add all the numbers together, and all the variables

14u-(2u-2)+7=0

We get rid of parentheses

14u-2u+2+7=0

We add all the numbers together, and all the variables

12u+9=0

We move all terms containing u to the left, all other terms to the right

12u=-9

u=-9/12

u=-3/4

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