4u+4-2(-3u-3)=4(u-1)

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Solution for 4u+4-2(-3u-3)=4(u-1) equation: 



4u+4-2(-3u-3)=4(u-1)

We move all terms to the left:

4u+4-2(-3u-3)-(4(u-1))=0

We multiply parentheses

4u+6u-(4(u-1))+6+4=0



We calculate terms in parentheses: -(4(u-1)), so:

4(u-1)

We multiply parentheses

4u-4

Back to the equation:

-(4u-4)



We add all the numbers together, and all the variables

10u-(4u-4)+10=0

We get rid of parentheses

10u-4u+4+10=0

We add all the numbers together, and all the variables

6u+14=0

We move all terms containing u to the left, all other terms to the right

6u=-14

u=-14/6

u=-2+1/3

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