4u+4-3(-3u-3)=5(u-1)

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Solution for 4u+4-3(-3u-3)=5(u-1) equation: 



4u+4-3(-3u-3)=5(u-1)

We move all terms to the left:

4u+4-3(-3u-3)-(5(u-1))=0

We multiply parentheses

4u+9u-(5(u-1))+9+4=0



We calculate terms in parentheses: -(5(u-1)), so:

5(u-1)

We multiply parentheses

5u-5

Back to the equation:

-(5u-5)



We add all the numbers together, and all the variables

13u-(5u-5)+13=0

We get rid of parentheses

13u-5u+5+13=0

We add all the numbers together, and all the variables

8u+18=0

We move all terms containing u to the left, all other terms to the right

8u=-18

u=-18/8

u=-2+1/4

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