4u-2+2(4u+2)=-6(u+1)

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Solution for 4u-2+2(4u+2)=-6(u+1) equation: 



4u-2+2(4u+2)=-6(u+1)

We move all terms to the left:

4u-2+2(4u+2)-(-6(u+1))=0

We multiply parentheses

4u+8u-(-6(u+1))+4-2=0



We calculate terms in parentheses: -(-6(u+1)), so:

-6(u+1)

We multiply parentheses

-6u-6

Back to the equation:

-(-6u-6)



We add all the numbers together, and all the variables

12u-(-6u-6)+2=0

We get rid of parentheses

12u+6u+6+2=0

We add all the numbers together, and all the variables

18u+8=0

We move all terms containing u to the left, all other terms to the right

18u=-8

u=-8/18

u=-4/9

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