4u-2+2(4u+4)=-4(u+2)

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Solution for 4u-2+2(4u+4)=-4(u+2) equation: 



4u-2+2(4u+4)=-4(u+2)

We move all terms to the left:

4u-2+2(4u+4)-(-4(u+2))=0

We multiply parentheses

4u+8u-(-4(u+2))+8-2=0



We calculate terms in parentheses: -(-4(u+2)), so:

-4(u+2)

We multiply parentheses

-4u-8

Back to the equation:

-(-4u-8)



We add all the numbers together, and all the variables

12u-(-4u-8)+6=0

We get rid of parentheses

12u+4u+8+6=0

We add all the numbers together, and all the variables

16u+14=0

We move all terms containing u to the left, all other terms to the right

16u=-14

u=-14/16

u=-7/8

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