4u-4=3(4-u)-2

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Solution for 4u-4=3(4-u)-2 equation: 



4u-4=3(4-u)-2

We move all terms to the left:

4u-4-(3(4-u)-2)=0

We add all the numbers together, and all the variables

4u-(3(-1u+4)-2)-4=0



We calculate terms in parentheses: -(3(-1u+4)-2), so:

3(-1u+4)-2

We multiply parentheses

-3u+12-2

We add all the numbers together, and all the variables

-3u+10

Back to the equation:

-(-3u+10)



We get rid of parentheses

4u+3u-10-4=0

We add all the numbers together, and all the variables

7u-14=0

We move all terms containing u to the left, all other terms to the right

7u=14

u=14/7

u=2

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