4u-5=2(2-u)-3

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Solution for 4u-5=2(2-u)-3 equation: 



4u-5=2(2-u)-3

We move all terms to the left:

4u-5-(2(2-u)-3)=0

We add all the numbers together, and all the variables

4u-(2(-1u+2)-3)-5=0



We calculate terms in parentheses: -(2(-1u+2)-3), so:

2(-1u+2)-3

We multiply parentheses

-2u+4-3

We add all the numbers together, and all the variables

-2u+1

Back to the equation:

-(-2u+1)



We get rid of parentheses

4u+2u-1-5=0

We add all the numbers together, and all the variables

6u-6=0

We move all terms containing u to the left, all other terms to the right

6u=6

u=6/6

u=1

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