4v+2(v-5)=-28

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Solution for 4v+2(v-5)=-28 equation: 



4v+2(v-5)=-28

We move all terms to the left:

4v+2(v-5)-(-28)=0

We add all the numbers together, and all the variables

4v+2(v-5)+28=0

We multiply parentheses

4v+2v-10+28=0

We add all the numbers together, and all the variables

6v+18=0

We move all terms containing v to the left, all other terms to the right

6v=-18

v=-18/6

v=-3

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