4v+2-2(-5v-1)=2(v-3)

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Solution for 4v+2-2(-5v-1)=2(v-3) equation: 



4v+2-2(-5v-1)=2(v-3)

We move all terms to the left:

4v+2-2(-5v-1)-(2(v-3))=0

We multiply parentheses

4v+10v-(2(v-3))+2+2=0



We calculate terms in parentheses: -(2(v-3)), so:

2(v-3)

We multiply parentheses

2v-6

Back to the equation:

-(2v-6)



We add all the numbers together, and all the variables

14v-(2v-6)+4=0

We get rid of parentheses

14v-2v+6+4=0

We add all the numbers together, and all the variables

12v+10=0

We move all terms containing v to the left, all other terms to the right

12v=-10

v=-10/12

v=-5/6

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