4v+2-2(-5v-2)=4(v-3)

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Solution for 4v+2-2(-5v-2)=4(v-3) equation:



4v+2-2(-5v-2)=4(v-3)
We move all terms to the left:
4v+2-2(-5v-2)-(4(v-3))=0
We multiply parentheses
4v+10v-(4(v-3))+4+2=0
We calculate terms in parentheses: -(4(v-3)), so:
4(v-3)
We multiply parentheses
4v-12
Back to the equation:
-(4v-12)
We add all the numbers together, and all the variables
14v-(4v-12)+6=0
We get rid of parentheses
14v-4v+12+6=0
We add all the numbers together, and all the variables
10v+18=0
We move all terms containing v to the left, all other terms to the right
10v=-18
v=-18/10
v=-1+4/5

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