4v+28=12v-12

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Solution for 4v+28=12v-12 equation: 



4v+28=12v-12

We move all terms to the left:

4v+28-(12v-12)=0

We get rid of parentheses

4v-12v+12+28=0

We add all the numbers together, and all the variables

-8v+40=0

We move all terms containing v to the left, all other terms to the right

-8v=-40

v=-40/-8

v=+5

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