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4v+2=(5-7v)
We move all terms to the left:
4v+2-((5-7v))=0
We add all the numbers together, and all the variables
4v-((-7v+5))+2=0
We calculate terms in parentheses: -((-7v+5)), so:We get rid of parentheses
(-7v+5)
We get rid of parentheses
-7v+5
Back to the equation:
-(-7v+5)
4v+7v-5+2=0
We add all the numbers together, and all the variables
11v-3=0
We move all terms containing v to the left, all other terms to the right
11v=3
v=3/11
v=3/11
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