4v+3(v+5)=29

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Solution for 4v+3(v+5)=29 equation: 



4v+3(v+5)=29

We move all terms to the left:

4v+3(v+5)-(29)=0

We multiply parentheses

4v+3v+15-29=0

We add all the numbers together, and all the variables

7v-14=0

We move all terms containing v to the left, all other terms to the right

7v=14

v=14/7

v=2

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