4v+32=9(v+3)

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Solution for 4v+32=9(v+3) equation:



4v+32=9(v+3)
We move all terms to the left:
4v+32-(9(v+3))=0
We calculate terms in parentheses: -(9(v+3)), so:
9(v+3)
We multiply parentheses
9v+27
Back to the equation:
-(9v+27)
We get rid of parentheses
4v-9v-27+32=0
We add all the numbers together, and all the variables
-5v+5=0
We move all terms containing v to the left, all other terms to the right
-5v=-5
v=-5/-5
v=1

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