4v+32=9(v+3)

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Solution for 4v+32=9(v+3) equation: 



4v+32=9(v+3)

We move all terms to the left:

4v+32-(9(v+3))=0



We calculate terms in parentheses: -(9(v+3)), so:

9(v+3)

We multiply parentheses

9v+27

Back to the equation:

-(9v+27)



We get rid of parentheses

4v-9v-27+32=0

We add all the numbers together, and all the variables

-5v+5=0

We move all terms containing v to the left, all other terms to the right

-5v=-5

v=-5/-5

v=1

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