4v+4=2v+22

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Solution for 4v+4=2v+22 equation: 



4v+4=2v+22

We move all terms to the left:

4v+4-(2v+22)=0

We get rid of parentheses

4v-2v-22+4=0

We add all the numbers together, and all the variables

2v-18=0

We move all terms containing v to the left, all other terms to the right

2v=18

v=18/2

v=9

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