4v-1+2(3v+2)=-5(v+3)

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Solution for 4v-1+2(3v+2)=-5(v+3) equation: 



4v-1+2(3v+2)=-5(v+3)

We move all terms to the left:

4v-1+2(3v+2)-(-5(v+3))=0

We multiply parentheses

4v+6v-(-5(v+3))+4-1=0



We calculate terms in parentheses: -(-5(v+3)), so:

-5(v+3)

We multiply parentheses

-5v-15

Back to the equation:

-(-5v-15)



We add all the numbers together, and all the variables

10v-(-5v-15)+3=0

We get rid of parentheses

10v+5v+15+3=0

We add all the numbers together, and all the variables

15v+18=0

We move all terms containing v to the left, all other terms to the right

15v=-18

v=-18/15

v=-1+1/5

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