4v-12=-2(v-2)

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Solution for 4v-12=-2(v-2) equation: 



4v-12=-2(v-2)

We move all terms to the left:

4v-12-(-2(v-2))=0



We calculate terms in parentheses: -(-2(v-2)), so:

-2(v-2)

We multiply parentheses

-2v+4

Back to the equation:

-(-2v+4)



We get rid of parentheses

4v+2v-4-12=0

We add all the numbers together, and all the variables

6v-16=0

We move all terms containing v to the left, all other terms to the right

6v=16

v=16/6

v=2+2/3

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