4v-12=5-(2v+4)

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Solution for 4v-12=5-(2v+4) equation: 



4v-12=5-(2v+4)

We move all terms to the left:

4v-12-(5-(2v+4))=0



We calculate terms in parentheses: -(5-(2v+4)), so:

5-(2v+4)

determiningTheFunctionDomain
-(2v+4)+5

We get rid of parentheses

-2v-4+5

We add all the numbers together, and all the variables

-2v+1

Back to the equation:

-(-2v+1)



We get rid of parentheses

4v+2v-1-12=0

We add all the numbers together, and all the variables

6v-13=0

We move all terms containing v to the left, all other terms to the right

6v=13

v=13/6

v=2+1/6

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