4v-2(4v+3)=6

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Solution for 4v-2(4v+3)=6 equation: 



4v-2(4v+3)=6

We move all terms to the left:

4v-2(4v+3)-(6)=0

We multiply parentheses

4v-8v-6-6=0

We add all the numbers together, and all the variables

-4v-12=0

We move all terms containing v to the left, all other terms to the right

-4v=12

v=12/-4

v=-3

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