4v-32=2(v-6)

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Solution for 4v-32=2(v-6) equation: 



4v-32=2(v-6)

We move all terms to the left:

4v-32-(2(v-6))=0



We calculate terms in parentheses: -(2(v-6)), so:

2(v-6)

We multiply parentheses

2v-12

Back to the equation:

-(2v-12)



We get rid of parentheses

4v-2v+12-32=0

We add all the numbers together, and all the variables

2v-20=0

We move all terms containing v to the left, all other terms to the right

2v=20

v=20/2

v=10

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