4v-4+2(6v+4)=-2(v+3)

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Solution for 4v-4+2(6v+4)=-2(v+3) equation: 



4v-4+2(6v+4)=-2(v+3)

We move all terms to the left:

4v-4+2(6v+4)-(-2(v+3))=0

We multiply parentheses

4v+12v-(-2(v+3))+8-4=0



We calculate terms in parentheses: -(-2(v+3)), so:

-2(v+3)

We multiply parentheses

-2v-6

Back to the equation:

-(-2v-6)



We add all the numbers together, and all the variables

16v-(-2v-6)+4=0

We get rid of parentheses

16v+2v+6+4=0

We add all the numbers together, and all the variables

18v+10=0

We move all terms containing v to the left, all other terms to the right

18v=-10

v=-10/18

v=-5/9

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