4v-6+2(4v+2)=-2(v+6)

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Solution for 4v-6+2(4v+2)=-2(v+6) equation: 



4v-6+2(4v+2)=-2(v+6)

We move all terms to the left:

4v-6+2(4v+2)-(-2(v+6))=0

We multiply parentheses

4v+8v-(-2(v+6))+4-6=0



We calculate terms in parentheses: -(-2(v+6)), so:

-2(v+6)

We multiply parentheses

-2v-12

Back to the equation:

-(-2v-12)



We add all the numbers together, and all the variables

12v-(-2v-12)-2=0

We get rid of parentheses

12v+2v+12-2=0

We add all the numbers together, and all the variables

14v+10=0

We move all terms containing v to the left, all other terms to the right

14v=-10

v=-10/14

v=-5/7

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