4v-6+2(6v+1)=-2(v+1)

Solution for 4v-6+2(6v+1)=-2(v+1) equation:

4v-6+2(6v+1)=-2(v+1)

We move all terms to the left:

4v-6+2(6v+1)-(-2(v+1))=0

We multiply parentheses

4v+12v-(-2(v+1))+2-6=0


We calculate terms in parentheses: -(-2(v+1)), so:

-2(v+1)

We multiply parentheses

-2v-2

Back to the equation:

-(-2v-2)


We add all the numbers together, and all the variables

16v-(-2v-2)-4=0

We get rid of parentheses

16v+2v+2-4=0

We add all the numbers together, and all the variables

18v-2=0

We move all terms containing v to the left, all other terms to the right

18v=2

v=2/18

v=1/9