4v-8+2(3v+1)=-2(v+8)

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Solution for 4v-8+2(3v+1)=-2(v+8) equation: 



4v-8+2(3v+1)=-2(v+8)

We move all terms to the left:

4v-8+2(3v+1)-(-2(v+8))=0

We multiply parentheses

4v+6v-(-2(v+8))+2-8=0



We calculate terms in parentheses: -(-2(v+8)), so:

-2(v+8)

We multiply parentheses

-2v-16

Back to the equation:

-(-2v-16)



We add all the numbers together, and all the variables

10v-(-2v-16)-6=0

We get rid of parentheses

10v+2v+16-6=0

We add all the numbers together, and all the variables

12v+10=0

We move all terms containing v to the left, all other terms to the right

12v=-10

v=-10/12

v=-5/6

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