4v-8+4(2v+1)=-4(v+3)

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Solution for 4v-8+4(2v+1)=-4(v+3) equation: 



4v-8+4(2v+1)=-4(v+3)

We move all terms to the left:

4v-8+4(2v+1)-(-4(v+3))=0

We multiply parentheses

4v+8v-(-4(v+3))+4-8=0



We calculate terms in parentheses: -(-4(v+3)), so:

-4(v+3)

We multiply parentheses

-4v-12

Back to the equation:

-(-4v-12)



We add all the numbers together, and all the variables

12v-(-4v-12)-4=0

We get rid of parentheses

12v+4v+12-4=0

We add all the numbers together, and all the variables

16v+8=0

We move all terms containing v to the left, all other terms to the right

16v=-8

v=-8/16

v=-1/2

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