4v2+16v=25

Solution for 4v2+16v=25 equation:

4v^2+16v=25

We move all terms to the left:

4v^2+16v-(25)=0

a = 4; b = 16; c = -25;
Δ = b2-4ac
Δ = 162-4·4·(-25)
Δ = 656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{656}=\sqrt{16*41}=\sqrt{16}*\sqrt{41}=4\sqrt{41}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-4\sqrt{41}}{2*4}=\frac{-16-4\sqrt{41}}{8}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+4\sqrt{41}}{2*4}=\frac{-16+4\sqrt{41}}{8}
$