If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4v^2+6v+1=0
a = 4; b = 6; c = +1;
Δ = b2-4ac
Δ = 62-4·4·1
Δ = 20
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{20}=\sqrt{4*5}=\sqrt{4}*\sqrt{5}=2\sqrt{5}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{5}}{2*4}=\frac{-6-2\sqrt{5}}{8} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{5}}{2*4}=\frac{-6+2\sqrt{5}}{8} $
| -6(x+9)-8=-62 | | 2^(x+3)=12 | | 5y+3+3y+7=12y-22 | | 4x=16/20 | | 5v2-27v+4=-6 | | 990/x=45 | | |m-7|+5=20 | | -4n+5n=-5 | | X+2=-14-3x | | Z14+x=21 | | -.875(-5x-6)=49 | | 4x+3,6-1,2=3x | | 6x+2+40+90+90=180 | | 8-3(4x+5)=9x | | .60(13x+11)=30 | | 2(u+4)-6u=-24 | | 5y+3(y-5)=-55 | | 0=-4+2r+2 | | 8m2-6m-9=0 | | -5(-6+6b)=210 | | k+6/25=1 | | 2/3x+Y=120 | | 20-4(2w+1)=7w-4(7+w | | P(x)=1 | | (4x-2)°=(5x-3)° | | 4(6+3x)=36 | | y-13-5y=7 | | .5(x-8)=17 | | 187+h=300 | | (v+6)^3-16=0 | | (2x+41)°=127 | | 119=3x+7x+9 |