4w(w+1)=2

Solution for 4w(w+1)=2 equation:

4w(w+1)=2

We move all terms to the left:

4w(w+1)-(2)=0

We multiply parentheses

4w^2+4w-2=0

a = 4; b = 4; c = -2;
Δ = b2-4ac
Δ = 42-4·4·(-2)
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{3}}{2*4}=\frac{-4-4\sqrt{3}}{8}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{3}}{2*4}=\frac{-4+4\sqrt{3}}{8}
$