4w(w=12)

Solution for 4w(w=12) equation:

4w(w=12)

We move all terms to the left:

4w(w-(12))=0

We multiply parentheses

4w^2-48w=0

a = 4; b = -48; c = 0;
Δ = b2-4ac
Δ = -482-4·4·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-48}{2*4}=\frac{0}{8}
=0
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+48}{2*4}=\frac{96}{8}
=12
$