4w-(w+29)=3(w+5)-(2w+4

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Solution for 4w-(w+29)=3(w+5)-(2w+4 equation: 



4w-(w+29)=3(w+5)-(2w+4

We move all terms to the left:

4w-(w+29)-(3(w+5)-(2w+4)=0

We get rid of parentheses

4w-w-(3(w+5)-(2w+4)-29=0

We add all the numbers together, and all the variables

3w-(3(w+5)-(2w+4)-29=0

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