4w2-534=1582

Solution for 4w2-534=1582 equation:

4w^2-534=1582

We move all terms to the left:

4w^2-534-(1582)=0

We add all the numbers together, and all the variables

4w^2-2116=0

a = 4; b = 0; c = -2116;
Δ = b2-4ac
Δ = 02-4·4·(-2116)
Δ = 33856
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{33856}=184$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-184}{2*4}=\frac{-184}{8}
=-23
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+184}{2*4}=\frac{184}{8}
=23
$