4x(10x-2)=192

Solution for 4x(10x-2)=192 equation:

4x(10x-2)=192

We move all terms to the left:

4x(10x-2)-(192)=0

We multiply parentheses

40x^2-8x-192=0

a = 40; b = -8; c = -192;
Δ = b2-4ac
Δ = -82-4·40·(-192)
Δ = 30784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{30784}=\sqrt{64*481}=\sqrt{64}*\sqrt{481}=8\sqrt{481}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8\sqrt{481}}{2*40}=\frac{8-8\sqrt{481}}{80}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8\sqrt{481}}{2*40}=\frac{8+8\sqrt{481}}{80}
$