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4x(2)-2x+1+3x(2)-8x=0
We add all the numbers together, and all the variables
7x^2-10x+1=0
a = 7; b = -10; c = +1;
Δ = b2-4ac
Δ = -102-4·7·1
Δ = 72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{72}=\sqrt{36*2}=\sqrt{36}*\sqrt{2}=6\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-6\sqrt{2}}{2*7}=\frac{10-6\sqrt{2}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+6\sqrt{2}}{2*7}=\frac{10+6\sqrt{2}}{14} $
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